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VistasI am exporting data from table convert to CSV, to JavaScript variable. . But getting Error "fputcsv() expects parameter 2 to be array" . How to do it?
This is my PHP code
<?php
require_once 'd:\xampp\htdocs\bpr\pdo_db.php';
$sql = "Select ID,FULL_NAMe,AGE from TRIAL";
$csv = get_csv_string($dbh, $sql);
echo "<script> var_csv='" . $csv . "' </script>";
function get_csv_string($dbh, $sql)
{
try
{
$result = $dbh->query($sql);
//return only the first row (we only need field names)
$row = $result->fetch(PDO::FETCH_ASSOC);
if ($row == null) {
return "No Data";
}
$f = fopen('php://memory', 'r+');
foreach ($row as $field => $value) {
if (fputcsv($f, $field) === false) {
return false;
}
}
//second query gets the data
$data = $dbh->query($sql);
$data->setFetchMode(PDO::FETCH_ASSOC);
foreach ($data as $row) {
if (fputcsv($f, $row) === false) {
return false;
}
} // end record loop
rewind($f);
$csv = stream_get_contents($f);
return rtrim($csv);
} catch (PDOExepction $e) {
return $e->getMessage();
}
return $csv;
}
I am getting following error!
Instead of fputcsv(), I made my own code. But issue if found when I save the CSV to a javascript variable. Is there any other way to convert the data to CSV and pass it on to javascript? I will convert this csv to JSON at Client side using javascript
·
Juan Pablo Isaza
1 Respuestas
Responde la pregunta0
You're trying to output a header row to CSV with the field names.
This code fails because you're looping through the $row array and attempting to write one field header at a time.
foreach ($row as $field => $value) {
if (fputcsv($f, $field) === false) {
return false;
}
}
What you want is an array with the field names in it. You can use array_keys() for that, so your code becomes
if (fputcsv($f, array_keys($row)) === false) return false;
No loop required.
·
Juan Pablo Isaza
Denunciar
Responde la pregunta